I know that there are 18 animals in the barnyard. Some are chickens and some are cows. I counted 50 legs in all. How many of the animals are chickens and how many are cows?
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34 comments:
the answer is something
This is hard.
well, first you have to know that cows have 4 legs and chikens have 2. than you divide??? i'm not sure. give me some time.
ok, i got 54 but i might have done it wrong. i divided 18 by 2 to get 9 so there are 9 of each animal. than i did 9 times 4 and 9 times 2 than added them to get 54 legs.
This sure keeps your mind thinking.
The question is how many animals are chickens and how many are cows? Carly, you are on the right track when you said you have to know that cows have 4 legs and chickens have 2. Do you mean 54 animals in the barnyard?
I understand how to do the problem now. It is just hard to get the answer how you want it. haha
P.S. carly I got the same as you, i suggest you keep trying...
I got it!!!! It is some of the most unexpected numbers. Keep trying everyone. You have keep on doing different problems. I am not going to give the answer so I dont spoil it....
I also got 54 so there are probably more of one animal then the other.
I had to do some real brainstorming. I wondered how I could get an extra or get rid of a pair of legs. It then all came to me.
I just got it too. I think there may be more than one answer though, but i haven't tried any other numbers that worked.
Same here noam, it just takes some thinking. I used like some much scrap paper. I think there just might be another answer also but sometimes there just isn't. You keep wanting to try different problems back and forth until you get closer and closer to what you are trying to figure out. If there are 18 animals and 50 legs, what do you use, multiplication, and i know, i am confusing.
never mind i don't think there is more than one answer anymore.
Well you never know. Although i am sure there is probably one answer now that I have done some more problems.
that's funny. I tried more numbers and i think there is not another answer, but i could be wrong.
ok, my dad just helped me get the answer. you do a whole bunch of stuff with algebra and variables if that helps anybody. just make it so x is chikens and y is cows. also use some order of operations. im not going to put the answer :).
Y'all have some great ideas!
You CAN use Algebra but you can also use other strategies like...make a chart.
I'll get you started:
4 legged animals - 1 2 3
2 legged animals - 17 16 15
continue the chart and see which combination gives you the number of legs you are looking for.
Some problems you don't even know how to start sometimes.And the first thing you need to do is understand the problem, and how to work with the problem. But what you do is use the information that the problem gives you first and it will give you some clues on what you need to do next.
What a great point, Sarah! It really is all about finding a place to start!
i think i might of gotten the answer
I GOT IT!!!
i started out with 10 cows and kept on going down
I might have gotten the answer!!! If you try really hard you will get the answer. write all your problems on a peice of paper. i will be easier!
This is very hard!!!!
I have it!!! It will take many tries to get the answer. Don't get mad if you get it wrong on your first try.
if you do 6 cows and 13 chikens...6 times 13........
i think that it has to be from 5-8 for the cows which is 20-32 legs, and 10-13chickens which is 20-26 feet.
i think i got it! if you add two numbers together and it eqals 18 then you can try multiplying the two numbers you chose and see if you get 50. if you don't get it your 1st time its ok! it took me a long time too!
Scotty-
6 cows and 13 chickens WOULD be 19 animals even though cows have 4 legs each so that is (6x4) 24 legs and chickens have 2 legs each (13x2)=26 legs and 24 legs +26 legs = 50 legs.
The number of legs checks, but the number of animals isn't correct.
Great thinking, though!
You have all worked hard to try to solve this one!!!!
If you look at all of the possibilities of animals that total 18 (like 1 and 17, 2 and 16, 3 and 15, 4 and 14, 5 and 13, 6 and 12, 7 and 11, 8 and 10, 9 and 9, 10 and 8, 11 and 7...
You will see that 11 chickens and 7 cows works because 11 chickens would be 22 legs (since chickens have 2 legs each 11 x 2) and 7 cows would be 28 legs (since cows have 4 legs each 7x4=28)and 22 legs +28 legs = 50 legs!
ha ha
7 cows 11 chickens
Its weird i think i might have already forgotten my answer! I hope it comes back to me, i wrote it down somewhere, now i just have to find that peice of paper....
Just to let you know I found it...
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